I am trying to setup a nested table function. So within the function I am passing a selected element and I want to select only the children/direct-descendants td/tr of that table and NOT the nested table\’s td/tr elements. Here is a little example that I setup.
<table class=\"top\">
<tr>
<td>1</td>
<td>2</td>
</tr>
<tr>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>
<table class=\"nested\">
<tr>
<td>1</td>
<td>2</td>
</tr>
<tr>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>4</td>
</tr>
</table>
</td>
</tr>
</table>
<div id=\"results\"></div>
and the jQuery / Javascript to go with it…
var tbl = $(\".top\");
var r = $(\"div#results\");
$(r).html(\"\");
$(r).append(\"var tbl = $(\\\".top\\\")</br>\")
$(r).append(\"$(tbl).find(\\\"td\\\").length:\" + $(tbl).find(\"td\").length.toString() + \"</br>\");
$(r).append(\"$(\\\"td\\\", tbl).length: \" + $(\"td\", tbl).length.toString() + \"</br>\");
$(r).append(\"$(tbl).children(\\\"tbody\\\").children(\\\"tr\\\").children(\\\"td\\\").length: \" + $(tbl).children(\"tbody\").children(\"tr\").children(\"td\").length.toString() + \"</br>\");
The results are as follows…
var tbl = $(\”.top\”) (to simulate the passed selector)
$(tbl).find(\”td\”).length:12 (selects ALL td elements)
$(\”td\”, tbl).length: 12 (selects ALL td elements, same as above)
$(tbl).children(\”tbody\”).children(\”tr\”).children(\”td\”).length: 6 (selects the proper elements, but the jQuery chain seems too long and strict for what I want to do)
Any help to find the proper selector for the children elements of the top level table is much appreciated! Thanks!





Rating:
The post html – jQuery with Nested Tables, select outer table tr/td with passed Selector appeared first on Javascript ASK.
via Javascript ASK http://javascriptask.phpfogapp.com/html-jquery-with-nested-tables-select-outer-table-trtd-with-passed-selector.html
No comments:
Post a Comment